TM 5-3895-382-24
Operation of No-Spin Differential
Straight Operation.
(1) Side gear. (2) Driven clutch. (7) Driven clutch. (8) Side gear.
(13) Spider. (18) Teeth of the spider. (19) Teeth of the driven
clutches.
When the machine drives straight forward (or backward) on
solid ground, both wheels provide tractive effort in moving the
machine. Teeth (18) on both sides of the spider (13) are fully
engaged with teeth (19) of driven clutches (2) and (7). The
teeth of cams (17) engage with teeth of center cam (11).
In this fully engaged condition, spider (13) turns both driven
clutches and side gears at the same speed as the ring gear.
The two side gears provide power to the axle shafts of the
wheel end assembles.
Operation While Turning
Operation While Turning.
(1) Side gear. (2) Driven clutch. (7) Driven clutch. (8) Side gear.
(13) Spider.
When the machine enters into a turn, the travel of the outside
wheel is further than the travel of the inside wheel. The
traction of the road forces the outside wheel to turn faster than
the speed of the ring gear. This movement of one wheel
turning faster than the other wheel starts the "clutch action" of
the no-spin differential.
The faster wheel causes side gear (1), and driven clutch (2) to
turn faster than the ring gear. The teeth of center cam (11)
work like ramps and the teeth of cam (17) move up the teeth of
the center cam.
This action causes the driven clutch to become disengaged
with the spider. The driven clutch pulls holdout ring (4) out of
the grooves in the center cam. The friction between the
holdout ring and driven clutch turns the holdout ring until notch
(16) in the holdout ring engages with spider key (15).
11-24
